3(22x^2+39x+10)=0

Solution for 3(22x^2+39x+10)=0 equation:

3(22x^2+39x+10)=0

We multiply parentheses

66x^2+117x+30=0

a = 66; b = 117; c = +30;
Δ = b2-4ac
Δ = 1172-4·66·30
Δ = 5769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5769}=\sqrt{9*641}=\sqrt{9}*\sqrt{641}=3\sqrt{641}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(117)-3\sqrt{641}}{2*66}=\frac{-117-3\sqrt{641}}{132}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(117)+3\sqrt{641}}{2*66}=\frac{-117+3\sqrt{641}}{132}
$